Math Q, How to Find the Power?

Hey, how do I find the power of something?

I have a base number, let's say it's 10 and 10 to the power of 2 is 100.

How could I have the sum (100) and the base (10) and get 2?

or 4 to the power of 3 = 64

So I'd have 4 and 64 and get 3?

Is this what you're after?

http://sourceforge.net/apps/mediawiki/construct/index.php?title=Expressions

No,

from the page:

^ Raise to power 8 ^ 2 (= 64)

I have the 8 and the 64, I need to be able to find out the 2

Thanks though.

I belive its called root. Lets say 10 ^2 = 100(10 to the power of 2 = 10^2). To get 10 would be the key ^ to (1/2):

100^(1/2) = 10.

To get 3 from 4 and 64: 64^(1/4) = 3

so its x^(1/n) where x is the sum and n the number, to get the power.

Hope this helped

Clever way to get your math homework done, isn't it.

What you're trying to find is the logarithm, not the power.

For 8^2 = 64, 8 is the base, 64 is the power and 2 is the exponent. The exponent equals the logarithm of the power as long as you don't change the base.

http://sourceforge.net/apps/mediawiki/c ... xpressions <-- Look under "Math".

Use ln for base e (Euler's number, approx. 2.718) or log for base 10.

For example: 10^x = 1000. To find x, just do:

log(1000)[/code:3jalj99k]
...which gives you 3.

If the base isn't 10 or [i]e[/i], use this instead: [code:3jalj99k]log(power) / log(base)[/code:3jalj99k]
(You can use [b]ln[/b] instead of [b]log[/b], the result should be the same.)

Using the example above, 8^2 = 64, you get [code:3jalj99k]log(64) / log(8)[/code:3jalj99k]
...and that should give you 2.

log is what you need as the above poster mentioned

<img src="http://www.purplemath.com/modules/logs/relatani.gif">

this is what it does, but you need to use the change of base relation

<img src="http://upload.wikimedia.org/math/5/6/f/56f7df21ad6bc1d3ce9ddff7ac5bb047.png">

the base k used doesnt matter, so ln or log (base 10) can be used interchangeably

Quasi, seems that site hates hotlinking.

<img src="http://images.icanhascheezburger.com/completestore/2008/2/21/fightdapowah128481029395156250.jpg">

Awesome! Thanks everybody!