Math - Camera boundary angle

I'm terrible at math and it is already quite late so could someone point me to the right direction with this.

Actually not object but screen center

So for short I would like to restrict camera from going over that line (scrollx,scrolly)

Ok well this should work.

Is between values:

angle(point1.x, point1.y, point2.x, point2.y)-angle(point1.x, point1.y, screen.x, screen.y)

Lower bound -180

Upper bound 0

What is the effect you are trying to achieve? I don't think I have a clear view, because there is the scroll to behavior which to me sounds the same thing: the camera never leaving the center point.

Could you explain exactly what it is you're trying to accomplish? Like the final goal that is?

roracle, That was quite bad explanation. I am restricting camera from going out from isometric map.

I'm making two assumptions here:

1) you want the camera to operate solely within the lower triangular area.

2) Your Layout is in 16:9 aspect ratio eg 960X540 **

using trigonometry:

Calculate the diagonal angle to be: 29.358 (trust me) we'll call this 'a'

from that we can use the tangent of the X value to set the Y value to draw the hypotenuse (your diag line)thus:

Y=X*tan(a)

So to fall within the triangular area you want the coordinates must be in the range:

camera.Y>camera.X*(0.5625) {0.5625 == tan 29.358}

So the short answer is:

camera.Y>camera.X*0.5625

Hope this makes it easier.

** Adjust the angle if different aspect ratio

bertie Booster, Actually that original post name doesn't make a lot of sense anymore

This picture represents the layout and that isometric map is half the height of that.

Ok my camera now works, but it is really ugly system. Specially for right side. And I leave this unsolved for now since I'm not sure about that aspect ratio thing.