Destroy all overlapping objects but one

Hello everybody ,

I'm currently searching on a compact way to *insert-title-here*

I have an object , and multiple instances of that object overlapping each others , how would I go about destroying all the overlapping instances but one ?

Thanks for reading and have a nice day !

Sprite: Is overlapping Sprite

Sprite: (invert) Is "Boolean name" - > sprite destroy

Sprite with boolean set to false will be destroyed

shinkan , your script isn't full , isn't it ?

You didn't set the boolean

you could invert a condition that normally picks one

like

+sprite | is overlapping sprite

+sprite | (invert) pick top instance           >sprite | destroy

You can't reveal all Your secrets. Must leave something to discover by others.

you could invert a condition that normally picks one

like

+sprite | is overlapping sprite

+sprite | (invert) pick top instance           >sprite | destroy

keepee ,

No , I don't think I'll work as intended , but I'll try it anyways !

My idea ,

• Pick all

-- (Invert) Pick instance 0

--- Destroy

Is there a specific instance you want to keep, or just random one?

shinkan , just a random one

To be honest , and if possible , I'm looking for a techique that doesn't involve variable usage

Whiteclaws

sorry, should have tested what I wrote before sending it.

"doesn't involve variable usage"

not even a non-static local variable?

you could store the UID of one of the objects overlapping and then invert a 'pick by UID' condition. Inverted pick by UID works, i've used it a few times.

use a loop and pick by ID as keepee says

Why not do this ?

For each element

• If overlapping a block

-- Destroy

Whiteclaws

no that's...

oh wait

yeah

that...

yes

Yes.

Correct.

You have won.

Congratulations.

Whiteclaws

Making worthless posts since 2013