Choosing a random layout.

I am making a game where layouts are chosen randomly from a pool of 250 layouts. When the game randomly chooses a layout, the game should not send the player to any menu layouts, or repeat previously chosen layouts. What's the easiest way to do what I want to do? I really don't want to create >250 events based off a randomly chosen variable.

nextroom as global variable

name your layouts 1,2,3, etc

Make a function: chooselayout

on function

set nextroom to

random(int(1,250))

Go to layout nextroom

—

Very helpful, but I ran into an error: i.imgur.com/xKxm3h0.png

—

Very helpful, but I ran into an error: i.imgur.com/xKxm3h0.png

You must have your global value set as text, set it as a number. You'll also have to set your variable as a string in the go to layout by name event. Use this:

str(nextlevel)

— I used <font face="Times New Roman, Times, serif">int(random(1,250))</font> and it accepted. I will report back with results.

— I used <font face="Times New Roman, Times, serif">int(random(1,250))</font> and it accepted. I will report back with results.

Sounds good, just curious, why do you have 250 layouts?

— The player must get through 100 different rooms per game, and having a pool of 250 allows for many unique playthroughs.

— The player must get through 100 different rooms per game, and having a pool of 250 allows for many unique playthroughs.

Like a dungeon crawler?

it is easier to use round than int. so basicly round(random(1,250)) . To save an event just use

onEvent -> go to layout "room"&round(random(1,250)).

Keep a global variable for the amount of rooms done.

Hi,

I think you might want to use some shuffling or helper storage, to avoid getting into the same room twice. Two ways (there are certainly more):

1) create array of size 250

2) fill it with consecutive integers

3) shuffle random pairs of a hundred or more times

4) make the player go from room to room, according to the (shuffled) order of elements in your array.

Way #2:

1- draw random integer as in examples you've seen above

2- if integer is already in the helper container (#3 below), repeat drawing

3- store the number in a helper array/string etc

4- proceed to the selected layout

Hope it helps,

Greg

mrPeanut

CJK

Thanks for the suggestions, I will report back once I try them out.