How do I create a game based on three screens?

Hello,

I want to create a game that consist in three screens (or maybe four) with static elements on each one where I would have to perform some actions (swipe, click, etc.).

I want to be able to swipe left and right in a infinite loop among the screens, I mean:

From screen 1 I can go to screen 4 or 2

From screen 2 I can go to screen 1 or 3

From screen 3 I can go to screen 2 or 4

From screen 4 I can go to screen 3 or 1

How can I do this on Construct 2?

Thanks in advance,

HerniHdez

You would either have to have a ridiculously large window/viewport size, or you would have to have 4 separate projects/games in separate browser windows. This is HTML5, not direct X, your options are going to be slim.

The idea is to deploy it only for smartphones and tablets, just swipe and go to another part of the shop.

Imagine a shop with 3 screens: Screen for requests and payments, screen for pick shirts/trousers and another screen to pick shoes/socks.

I'm not sure if Construct 2 is going to be the best platform to build a game of this kind.

Oh, I thought you meant like 3 monitors. Look at tutorials on swipe and scroll. Or search the forum. For me I put an invisible sprite with scrollTo on it. Then I just move it where I need the screen to scroll.

Ohhh... probably I explain wrong

As you say I don't mean 3 monitors, I mean one monitor or screen on a smartphone or tablet, scroll across a scenary, and from last part of the scroll see again the first, in a circular way.

And scroll should be per zones, i mean, swipe should scroll an exact amount of pixels to center the next part of the scene on the screen.

Herni do you mean Screen Switching like this

Hello Lordshiva1948,

Thanks for the file

I mean something like this: The examples are here:

* * Yesterday, I was able to do something like the first example (no smooth), still trying to make it smooth, but I still don't know how to make it cycle, I mean when I am in top left, swipe to left move me to the top right and viceversa. 1>2>3>4>1>2... 2<3<4<1<2<3.

Thanks again

Herni