Hey, thank you very much for playing it, controls are listed in question icon that located on top of the game screen but may be i should write it in game too. Yes game is hard, but its so satisfying when you finally dodged that obstacles you were struggling forever! And with practice you start to feel 6-th sense about obstacles and game becomes much easier

Hello everybody, i creating this game for fun but its really hard to test it alone. If you dont mind games like impossible game or geometry dash then i invite you to test out my game. Who knows, may be one of you will be first person who manages to finish the first level <img src="{SMILIES_PATH}/icon_e_biggrin.gif" alt=":D" title="Very Happy">

Play my game here: https://www.scirra.com/arcade/action-ga ... beta-13478

Feedback is much appreciated, and thanks for playing! Rate this game if you think that its a worthy one <img src="{SMILIES_PATH}/icon_rolleyes.gif" alt=":roll:" title="Rolling Eyes">

after some time i tried to create new foreground layer and started to paint tilemap on it that will hide character to create depth effect but its not an ideal solution because i had to increase collision box of walls and now its become not very realistic.

if someone has suggestion on tilemap z ordering i will be gratefull.

Oh, i could not open file because its 218 version while i have 216. I also tried Zenox98's way and its wonderfully works on one sprite but when i want to add family or tilemap its not working.

So you can only do one or another option? i mean you cant get behind a wall that you put to bottom and you cant get to front of a wall that you put to top of the layer. But i wanted to know is that possible to be invisible behind a wall and be visible in front of it? Like in old isometric 2d games

First of all i am total newbie in game development. May be there is many topics about this but i could not find anything that i found helpfull. Everything is fine from front but when character walks behind the wall i can see him through. Is there easy way to fix this?