How do I use a variable in a Ajax request ?

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WeedMan

- Laurent
- - Joined 18 Jan, 2012
  - 129 topics • 544 posts
- 1
- 11 Feb, 2023
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In my project, I use Ajax request a lot, but according to player choice, the requested project file is always different.

In the following expression, how can I use a variable instead of testFr.srt filename ? For example, filename could be testFr1.srt or testFr2.srt...

-> AJAX: Request testFr.srt (tag "subFr")

Can I use Request URL instead ? And if yes, what would be the adress to a project file named testFr.srt
Tagged:

ajax
- dop2000
- - Joined 26 May, 2016
  - 139 topics • 12,609 posts
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- 12 Feb, 2023
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Yes, use "Request URL" and put the filename testft.srt into the text variable.

Or you can use something like this:
Variable lang = Fr AJAX Request URL "test" & lang & ".srt"

If the file is in a sub-folder, you need to include it too, for example:

AJAX Request URL "Subtitles/testFr.srt"
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- Laurent
- - Joined 18 Jan, 2012
  - 129 topics • 544 posts
- 1
- 12 Feb, 2023
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Amazing !

thanks for confirming this intuition :)

(the subfolder trick doesn't work, though)
- dop2000
- - Joined 26 May, 2016
  - 139 topics • 12,609 posts
- 2
- 12 Feb, 2023
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Check "Export file structure" in project properties. If it's set to "flat", you don't need to specify subfolder name.
- Laurent
- - Joined 18 Jan, 2012
  - 129 topics • 544 posts
- 2
- 13 Feb, 2023
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Thank you !

Construct is full of subtilities :)