Ajax problem

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  • 8 posts

  • Hi

    I've used like 4 hours to get some ajax to work, but it doesn't seems to work..

    And my not working i mean that i can set (this.data) in the .done(result) function, when the ajax is done, and the data is pulled.

    I finally ended up using HttpRequest, but why doesn't this work ?

    -Jesper

    Acey

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  • You've literally given zero information about what's working, and what's not working.

    I've used the AJAX Object successfully, quite a bit.

    If you give a more concrete example, I'm sure we can all help.

    -john

  • Official Ajax plugin works fine. You might reference it.

  • $.ajax({
	url: "http://api.openweathermap.org/data/2.5/weather?apikey=" + apikey + "&lat=" + lat + "&lon=" + lng,
    method: "get"
}).done(function (res) {
	this.result = res;
	        
	console.log(res);
}).error(function (result) {
	        
});[/code:2ey1evvz]

I tried this code. But i wasn't able set "this.result" to anything from inside the done function.

I've looked at the Ajax plugin, and that uses HttpRequest too, just wondered why this didn't work, since i was able to pull the data correctly when i tried "console.log(res)".

  • Acey

    Add "var self=this;" , and replace "this" by "self" in callback function.

    var self=this;
$.ajax({
   url: "http://api.openweathermap.org/data/2.5/weather?apikey=" + apikey + "&lat=" + lat + "&lon=" + lng,
    method: "get"
}).done(function (res) {
   self.result = res;
          
   console.log(res);
}).error(function (result) {
          
});[/code:1r8riod9]

  • Acey

    Add "var self=this;" , and replace "this" by "self" in callback function.

    var self=this;
$.ajax({
   url: "http://api.openweathermap.org/data/2.5/weather?apikey=" + apikey + "&lat=" + lat + "&lon=" + lng,
    method: "get"
}).done(function (res) {
   self.result = res;
          
   console.log(res);
}).error(function (result) {
          
});[/code:2xc0jwrl]

    Can you maybe explain why this should work, so you just set var self to this?

  • I might not explain clearly.

    "this" had been override in callback, it was not the same object as you expect. So using another variable to store the "this" reference.

  • I havne't tried it, but that sounds correctly, thank you

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