Set angle towars opposite side of the screen

I have this cose:

Set position to x=choose(0,LayoutWidth) y=choose(0,LayoutHeight)

Which positions the tiled background on one of the corners, I now need to rotate it towards the opposite angle. The hotspot is on the left-corner so:

Position x=0,y=100 the opposite corner should be on x=100, y=0.

To do it I did this:

Set angle toward: x=abs(self.X-LayoutWidth) y=abs(self.Y-LayoutHeight)

but it isn't correct because the background is now positioned diagonally, how can I fix this?

Thanks and I hope I was able to explain myself.

why don't you put the hotspot of the tiledbg in the middle and just do a

set angle to floor(random(4))*90 ?

No because randomly putting a random angle won't fix the issue becuase since the position is also random it may not end in the right angle.. I need the hostpot in the top-left corner because I'm using sine to make it grow an reduce it for a special effect.

ok (:

could help to have at least some visual to be sure but let see

if you're on :

• top left (0,0) angle should be 0
• top right (layoutwidth,0) angle should be 90
• bottom right (layoutwidth,layoutheight) angle should be 180
• bottom left (0,layoutheight) angle should be 270

so then hmmm I see

+When you want
  -> tiledBg: set position to choose(-1,1),choose(-1,1)
  -> tiledBg: set angle to angle(0,0,self.X,self.Y)+135
  -> tiledBg: set position to clamp(self.X,0,1)*layoutWidth,clamp(self.Y,0,1)*layoutHeight

Thanks, I understand everything. Thanks really, there is a problem when the background goes to LayoutWidth / LayoutHeight but I'll work it out!

Thanks truly