How to parse elements in an array

Hi,

I have a sequence of numbers stored in an array as single numbers for each element. I'm trying to search for consecutive number of matches. Example:

1 2 3 3 3 2 2 3 3 2 2 2 1 1 1 1

The result would be:

three 3s

two 2s

two 3s

three 2s

four 1s

Also, the sequence of numbers can have varying lengths.

I've tried using WHILE but to no avail as the condition to stop the WHILE loop doesn't seem to work:

WHILE

array.at(index) NOT EQUAL TO 0 (action)

In the action, I increment index.

I'm trying to check for matches while not end of sequence taking 0 to be the end of the sequence. By the way, if the array element is empty,is it still a '0' or a NULL?

Any help rendered will be greatly appreciated.

I'm still learning about arrays myself, but I tend to use these kind of conditions:

array - for each xy

system compare : array.curY is 0

system compare : array.curvalue is not 0

• set array2.At(array.curX,array.curY) : 25*Array.curvalue

I would go with something like

array count

BUT

this is rougher than I feel after a night out and this is not finished - it needs to checks the last number sent - probably the cheapest way would be to force a number at the end that is never going to normally be there...(which I have done here in a very elegant way <img src="smileys/smiley9.gif" border="0" align="middle"> )

I expect there is a much better way - but its a start if no one else comes along...

Actually what I need to know is how do you compare two consecutive elements in an array?

something like (not tested)

system compare two values

array.curvalue (comparison) array.at.array(currentX+1) ?

Almost right.

array test 2 - didn't take as long as the last one to do ! <img src="smileys/smiley1.gif" border="0" align="middle">

It is rather simple:

copy.com/OqrKHoesNdWpheF8

Thanks a lot guys. You have been a great help.