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  • tarek2

    I can't understand one thing: in your script, you use 3 variables (Sequence1/Sequence2/Sequence3) and you store the corresponding Array values in these variables. However, I can't find it in the script when you use these variables.

    I think that in this case, I would just change the name of these variables by my variables (seq1/seq2/seq3),

  • Hi tarek2

    Thanks for replying and also for all the explanation!

    So, my system already sorts the sequences so I wouldn't need to do this process again, through your solution. In that case, since my variables (seq1/seq2/seq3) already contain the values ​​of the sequences, I wouldn't need to use the Array to store them, right?

    EDITED: I also have the starting numbers in my script and the variable already stores the sequence number of each frame.

  • Hi tarek2

    Right in the bull's eye! That's exactly it. Thank you very much!!!!

    The only issue is that in the example the sequences are drawn, but in my case, I already have these values ​​allocated to variables (seq1/seq2/seq3). It is possible to change the script to use these values ​​instead of drawing them, right?

  • Hi everybody

    I have a problem to solve and I would like to ask for some help from you.

    I have a sequence of frames and three options that change the order of this sequence according to the positioning of each frame. I need to register the result of the last change in a variable.

    For example, the first frame sequence is 3210 (i.e. frame 3 at position 1, frame 2 at position 2, frame 1 at position 3, and frame 0 at position 4)

    Then appears the first sequence changer (1432) that will define the positions of the frames of the first sequence of frames (3210). Based on this initial sequence, frame 3, which is the one in position 1, remains in it. Then we have frame 0, which is in position 4, then frame 1 which is in position 3, and frame 2 which is in position 4. Result: 3012

    A new sequence changer appears: 2314. This will change the result of the previous sequence (3012) to 0132

    Finally, the last sequence changer: 4132, which will transform the result of the penultimate sequence changer to 2031

    It is this last value (in this case, 2031) that I need access to.

    Could someone give me suggestions on how to get this sequence in the background and only receive the final value?

  • Is it possible to record each frame change from the letter sequence to step 4?

    For example:

    1) ADCB - Letter Sequence

    2) 3124 - First change of position (CADB) - Frames: 2013

    3) 4123 - Second Amendment (BCAD) - Frames: 1203

    4) 1324 - Third Amendment (BACD) - Frames: 1023

    Based on the information from the frames from step 4, I can assemble the sequence of letters in step 5.

    EDITED: Sorry. I didn't see your post before. I think this is the simpler way to solve this.

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  • Hi R0J0hound

    I think I managed to simplify the problem in a way that you can just tell which way I should go to solve it.

    The interface is made up of:

    1) randomly shuffled sequence of letters (ABCD) (eg CDAB appeared in the draw (which corresponds to frames 2301))

    2) 3 blocks of 4 random numbers from 1 to 4, a sequence of which is drawn. (eg 4213/3214/2134 - the last one was drawn and a list of frame numbers was saved in a variable)

    3) 4 numbers that serve as parameters for a new position change (eg 4321 - a list of frame numbers saved in a variable)

    4) 3 blocks of 4 random numbers from 1 to 4, a sequence of which is drawn. (eg 1234/2413/3142 - the last one was drawn and a list of frame numbers was saved in a variable)

    5) Randomly shuffled sequence of letters (ABCD) or we can leave them all in frame 0 and then adjust according to the formation of the stage 4)

    Making a simulation of the process based on the data previously informed and with the user selecting the correct options:

    1) CDAB

    2) 2134 (corresponds to DCAB)

    3) 4321 (BACD)

    4) 3124 (CBAD)

    5) Sequence of letters that corresponds to the positions of stage 4, that is, the sequence that will form the CBAD if we change the positions of the letters from the bottom to the top.

    In this case the correct solution would be BACD. This is the sequence that should appear below.

    I need to know how to register these frame changes at each stage. If I have this stage 4 value, I can use it to form the letters that are in stage 5 and when I do the reverse order, I would have to hit the bottom with the letters at the top. Do you think it's clearer now?

  • I appreciate the offer but I’m a bit pressed for time lately. No coffees needed. I’m actually considering getting rid of that since I’m happy to help as I have time usually. I can try to have a look again one of these days. It’s just not a fun problem to work on and I’ve created more work for myself since I haven’t been able to create something that is easy to understand or use.

    I burn out on projects pretty quick, even the ones I enjoy. But I’ll see if I can get a chance to look at this again later.

    I would really appreciate it. I know it's a lot of work to develop something that meets these new possibilities, but unfortunately, I only need to solve this one to be able to show my idea. I've almost given up several times, but I need to insist a little more and that's why I'm asking you to help me with this. I think the "coffees" are a great way for people to give some form of retribution for your help. I'm totally comfortable with it.

  • Hi R0J0hound,

    Will you accept some coffee to help me solve this problem? If so,

    how many coffees would it be?

  • If anyone else has any ideas on how to resolve this I would be grateful to hear your suggestions. I'm still stuck here. :(

  • Ok. Please let me know if you have any ideas on how to turn this into the new format (2 lines). I'll keep making my attempts around here

  • Hi R0J0hound

    Thank you for replying

    OK. I understand what you said, but even though it's a new row of options I have to leave it in the same sprite as the others? Because in that case, I would have to select two options (1 in the top row and one in the bottom row).

  • Hi R0J0hound

    Thanks a lot for the last example. I've been studying this file and I've also made some changes to my event sheet to make it look more like your solution, however, I'm looking to raise the difficulty once again and ended up getting stuck. I've duplicated your file already in the format it should be (two lines of options instead of 1), but the rest remains the same. I decided to clone the sprite to use in the other row, but I can't make it draw the numbers. The idea is that one of the options from the top row and another from the bottom row arrive in the final result. Could you take a look?

    we.tl/t-ZqYIS3lFi1

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RBuster

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