制作一个简单的开门开关

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Published on 6 Apr, 2013. Last updated 25 Feb, 2019

事件制作

制作一个类似下面这张截图的事件:

offset (0, 1)是判断角色是否站在开关的上面。如果条件成立,就把门打开(消除),开关按下(也是消除)。

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